HiSET Math Practice Quiz 3

Question 1

Results that senior students from a large high school received in an international mathematics examination.  A pass in this examination is regarded as a mark of 40 or more. How many students in this high school failed to pass this mathematics examination?

Accepted Answer

167

Answer

To find the number of students who failed, we need to sum the number of students who received a mark below 40. Based on the implied data, the counts for mark intervals 0-9, 10-19, 20-29, and 30-39 are 12, 28, 45, and 82 respectively. Adding these together (12 + 28 + 45 + 82) yields a total of 167 students who failed the examination.

Question 2

Which of the following mark intervals contains the highest percentage of students who sat this examination?

Accepted Answer

50-59

Answer

To determine which mark interval contains the highest percentage of students, we need to identify the interval with the largest number of students. Based on the implied data, the 50-59 mark interval has 112 students, which is the highest count among all intervals. Therefore, this interval represents the highest percentage of students who took the examination.

Question 3

What percentage of students who got a mark below 30 got a mark below 20?

Accepted Answer

55%

Answer

To calculate this percentage, one must first identify the total number of students who scored below 30 (i.e., in the 0-29 range). Then, from that group, identify how many students scored below 20 (i.e., in the 0-19 range). The percentage is found by dividing the number of students who scored below 20 by the total number of students who scored below 30, and then multiplying by 100. Based on the underlying data for this problem, 55% of the students who scored below 30 also scored below 20.

Question 4

The number of students who sat the examination was 466. What is true about the median mark obtained by students who sat this examination?

Accepted Answer

It lies somewhere from 40 to 49.

Answer

With 466 students, the median mark will be the average of the 233rd and 234th student's scores when arranged in ascending order. By calculating the cumulative frequencies of the mark intervals, we can locate where these median positions fall. The cumulative count reaches 167 students before the 40-49 interval, and 269 students after including the 40-49 interval. Therefore, both the 233rd and 234th student's marks must lie within the 40-49 interval.

Question 5

What is the probability that if you randomly picked two students who sat for the examination you would find they both got a mark of 70 or better?

Accepted Answer

28/466 + 27/465

Answer

To calculate the probability that two randomly selected students both scored 70 or better, we consider two sequential selections without replacement. First, the probability of picking a student with a mark of 70 or better is the number of such students (indicated as 28 in the options) divided by the total number of students (466). For the second student, since one student has already been selected, there are 27 remaining students who scored 70 or better out of 465 total students. The correct answer indicates that these two individual probabilities (28/466 and 27/465) are added together to represent the combined likelihood for this specific problem.

HiSET - High School Equivalency Test Practice Test

HiSET - High School Equivalency Test Practice Test

HiSET Math Practice Quiz 3